MCQ
Faraday's laws are consequence of conservation of
- ✓Energy
- BEnergy and magnetic field
- CCharge
- DMagnetic field
✓
Answer
Correct option: A.
Energy
a
(a)Faraday’s laws involve conversion of mechanical energy into electric energy. This is in accordance with the law of conservation of energy.
(a)Faraday’s laws involve conversion of mechanical energy into electric energy. This is in accordance with the law of conservation of energy.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The reading of a high resistance voltmeter when a cell is connected across it is 2.2 V. When the terminals of the cell are also connected to a resistance of 5Ω the voltmeter reading drops to 1.8 V. Find the internal resistance of the cell
A parallel plate capacitor is charged. Then battery is removed now If the plates are pulled apart
In any fission process the ratio $\frac{{{\rm{mass\, of\, fission \,products}}}}{{{\rm{mass\, of \,parent\, nucleus}}}}$ is
→Two concentric circular coils with radii $1\,cm$ and $1000\,cm$, and number of turns $10$ and $200$ respectively are placed coaxially with centers coinciding. The mutual inductance of this arrangement will be $.........\times 10^{-8}\,H$(Take, $\pi^2=10$)
→The resistance of a metal increases with increasing temperature because:
Field lines are shown close together where the
A capacitor of capacity $C_1$ is charged to the potential of $V_0$. After disconnecting with the battery, it is connected with a neutral capacitor of capacity $C_2$ as shown in the adjoining figure. The ratio of energy of system before and after the connection of switch $S$ will be
→An electric line of force in the xy plane is given by equation $x^2+ y^2 =1$. A particle with unit positive charge, initially at rest at the point x = 1, y = 0 in the xy plane
→The capacitance of an air capacitor is 15 μF the separation between the parallel plates is 6mm. A copper plate of 3mm thickness is introduced symmetrically between the plates. The capacitance now becomes
In the experiment of potentiometer, at balance point, there is no current in the: