MCQ
$Fe(OH)_2$ is precipitated from $Fe(II)$ solutions as a while solid but turns dark green and then brown due to the formation of
- A$Fe(OH)_2$ and $Fe(OH)_3$
- Bonly $Fe(OH)_3$
- ✓$Fe_2O_3. (H_2O)_n$
- D$Fe_2O_3 ·2H_2O$
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(Given atomic number: $\mathrm{C}: 6, \mathrm{Na}: 11, \mathrm{O}: 8$, $\mathrm{Fe}: 26, \mathrm{Cr}: 24 \mathrm{~J}$