Figure $(i)$ below shows a Wheatstone's bridge in which $P, Q, R$ and $S$ are fixed resistances, $G$ is a galvanometer and $B$ is a battery. For this particular case, the galvanometer shows zero deflection. Now, only the positions of $B$ and $G$ are interchanged, as shown in figure $(ii)$. The new deflection of the galvanometer
KVPY 2010, Medium
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(c)

In case $(i)$, galvanometer shows zero deflection.

$\therefore V_B=V_D$

$\Rightarrow \frac{P}{S}=\frac{Q}{R} \quad \dots(i)$

When battery $B$ and galvanometer $G$ are interchanged, position of galvanometer is as shown below,

Now, ratio of resistances across galvanometer is

$\frac{S}{P} \text { and } \frac{R}{Q}$

As from Eq. $(i)$, $\frac{S}{P}=\frac{R}{Q}$

Hence, galvanometer still shows zero deflection because Wheatstone's bridge is balanced.

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