
- AWill remain zero.
- BWill become positive.
- CWill become neagative.
- DWill become undefined.

Explanation:
Charge distribution:

Due to charge distribution, intersection by the closed surface of conducting sphere containing the positive charge. So we can say that the flux of the electric field through the closed surface will become positive.
$\therefore\phi=\frac{\text{q}_{\text{in}}}{\in_0}\Rightarrow+\text{ve}$
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