Question
Figure, shows a person standing somewhere in between two identical tuning forks, each vibrating at $512\ Hz.$ If both the tuning fbrks move towards right at a speed of $5.5m/s,$ find the number of beats heard by the listener. Speed of sound in air $= 330m/s.$

Answer


According to the data, $V_s = 5.5\ m/s$ for each turning fork.
So, the apparent frequency heard from the tuning fork on the left,
$\text{f}\ '=\Big(\frac{330}{330-5.5}\Big)\times512=527.36\ \text{Hz}=527.5\ \text{Hz}$
Similarly, apparent frequency from the tunning fork on the right,
$\text{f}\ '=\Big(\frac{330}{330-5.5}\Big)\times512=510\ \text{Hz}$
So, beats produced $527.5-510=17.5\ \text{Hz}.$

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