Question
Find: $\int \frac{d x}{\sqrt{x}+x}$

Answer

$\int \frac{d x}{\sqrt{x}+x} d x=\int \frac{1}{\sqrt{x}(1+\sqrt{x})} d x$
Let, $1+\sqrt{x}=t$
$\begin{aligned} 0+\frac{1}{2 \sqrt{x}} d x & =d t \\ \frac{1}{\sqrt{x}} d x & =2 d t \\ & =2 \int \frac{1}{t} d t \\ & =2 \log t+C \\ & =2 \log (1+\sqrt{x})+C\end{aligned}$

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