Find out current in $3\,\Omega $ resistance in given circuit
Medium
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$\mathrm{R}_{\mathrm{eq}}=[(4+2) \| 3]+5$
$=7\, \Omega$
$I=\frac{14}{7}=2 \,A$
$I_{1}=\frac{6}{9} \times 2=\frac{4}{3} \,A$
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