$A$ and $B$ are two square plates of same metal and same thickness but length of $B$ is twice that of $A$. Ratio of resistances of $A$ and $B$ is
Medium
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(c) ${R_A} = \frac{{\rho l}}{{l \times t}} = \frac{\rho }{t}$ and ${R_B} = \frac{{\rho \times 2l}}{{2l \times t}} = \frac{\rho }{t}$ i.e. $\frac{{{R_A}}}{{{R_B}}} = 1:1$
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