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Arithmetic Progressions — Maths STD 10 — Question

Gujarat BoardEnglish MediumSTD 10MathsArithmetic Progressions2 Marks
Question
Find the $30^{th}$ term of an $A P\ 10,7,4,....$
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Answer

For the given $AP\ 10, 7, 4, ..., a = 10$
$d = 7 - 10 = - 3$ and $n = 30$
$\therefore a_n=a+(n-1) d$
$\therefore a_{30}=10+(30-1)(-3)$
$= 10 + (29)(- 3)$
$=10-87$
$=-77$
Thus the $30^{th}$ term of an $AP$ is $-77.$

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