Question
Find the cube$-$root of $\frac{27}{64}$

Answer

$ \frac{27}{64}$
$ =\sqrt[3]{\frac{27}{64}}$
$ =\frac{\sqrt{3 \times 3 \times 3}}{\sqrt{4 \times 4 \times 4}}$
$ =\frac{3}{4}$

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