Question
Find the remainder when $2x^3 – 3x^2 + 4x + 7$ is divided by $x + 3$

Answer

$f(x) = 2x^3 – 3x^2 + 4x + 7$
Let $x + 3 = 0,$ then $x = – 3$
Substituting the value of x in $f(x)$
$f(–3) = 2(–3)^3 – 3(–3)^2 + 4(–3) + 7$
$= 2 x (–27) – 3(9) + 4(–3) + 7$
$= –54 – 27 – 12 + 7$
$= – 93 + 7$
$= – 86$
$\therefore $ Remainder $= – 86.$

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