Question
Find the solution of the equation $5(3+y)=20+y$.
✓
Answer
We have, $5(3+y)=20+y$
$\Rightarrow \quad 15+5 y=20+y$
$\Rightarrow \quad 5 y-y=20-15\quad$ [transposing $y$ to LHS and 15 to RHS]
$\Rightarrow \quad 4 y=5$
$\therefore \quad y=\frac{5}{4} \quad$ [dividing both sides by 4]
Thus, solution of the given equation is $\frac{5}{4}$.
$\Rightarrow \quad 15+5 y=20+y$
$\Rightarrow \quad 5 y-y=20-15\quad$ [transposing $y$ to LHS and 15 to RHS]
$\Rightarrow \quad 4 y=5$
$\therefore \quad y=\frac{5}{4} \quad$ [dividing both sides by 4]
Thus, solution of the given equation is $\frac{5}{4}$.
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