Question
Find the value of x in the trapezium ABCD given below.
Image

Answer

In the trapezium $A B C D$, we have
$A B \| C D$
Also, sum of interior angles $B$ and $C$ is $180^{\circ}$.
$\therefore(x+20)^{\circ}+(x-30)^{\circ}=180^{\circ}$
$\Rightarrow \quad 2 x^{\circ}-10^{\circ}=180^{\circ}$
$\Rightarrow \quad 2 x^{\circ}=190^{\circ}$
$\Rightarrow \quad x^{\circ}=95^{\circ}$

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