MCQ
Finely divided iron combines with $CO $ to give
- ✓$Fe{(CO)_5}$
- B$F{e_2}{(CO)_9}$
- C$F{e_2}{(CO)_{12}}$
- D$Fe{(CO)_6}$
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$2 \mathrm{NO}_{(\mathrm{g})}+2 \mathrm{H}_{2(\mathrm{~g})} \rightarrow \mathrm{N}_{2(\mathrm{~g})}+2 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{g})}$
|
$[NO]$ $\mathrm{mol} \mathrm{L}^{-1}$ |
${H}_{2}$ $\mathrm{mol} \mathrm{L}^{-1}$ |
Rate $\mathrm{mol}L^{-1}$ $s^{-1}$ |
|
| $(A)$ | $8 \times 10^{-5}$ | $8 \times 10^{-5}$ | $7 \times 10^{-9}$ |
| $(B)$ | $24 \times 10^{-5}$ | $8 \times 10^{-5}$ | $2.1 \times 10^{-8}$ |
| $(C)$ | $24 \times 10^{-5}$ | $32 \times 10^{-5}$ | $8.4 \times 10^{-8}$ |
The order of the reaction with respect to $\mathrm{NO}$ is ..... .
$(I)$ ${O_3} \to $ product
$(II)$ $C{r_2}O_7^{2 - }\xrightarrow{{{H^ + }}}$ product
$(III)$ $MnO_4^\Theta \xrightarrow{{{H^ + }}}$ product
$(IV)$ $H_2S \longrightarrow $ product
