STD 11 - 3. Classification of elements and periodicity in properties — JEE STD 11 Science — Question

$2NO + Br \to 2NOBr$ is

$NO + Br_2 \rightleftharpoons NOBr_2$ (Fast)

$NOBr_2 + NO \to 2NOBr$ (Slow)

The rate law expression is

Given                                                                                                   $\Delta H$

$(i)\, Fe_2O_{3(s)}+3C_{(graphite)} \to 2Fe_{(s)} + 3CO_{(g)}$         $492\, kJ/mol$

$(ii)\, FeO_{(s)}+C_{(graphite)} \to Fe_{(s)} + CO_{(g)}$                     $156\, kJ/mol$

$(iii)\, C_{(graphite)} + O_{2(g)} \to CO_{2(g)}$                                   $-393 \,kJ/mol$

$(iv)\, CO_{(g)} + \frac{1}{2}\, O_{2(g)} \to CO_{2(g)}$                            $-283\, kJ/mol$