Download App

13. probability — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths13. probability1 Mark
MCQ
For a biased die the probabilities for different faces to turn up are given below

$Face:$ $1$ $2$ $3$ $4$ $5$ $6$
$Probability:$ $0.1$ $0.32$ $0.21$ $0.15$ $0.05$ $0.17$

The die is tossed and you are told that either face $1$ or $2$ has turned up. Then the probability that it is face $1$, is

  • ✓
    $\frac{5}{{21}}$
  • B
    $\frac{5}{{22}}$
  • C
    $\frac{4}{{21}}$
  • D
    None of these
✓

Answer

Correct option: A.
$\frac{5}{{21}}$
a
(a) Required probability $ = \frac{{0.1}}{{0.1 + 0.32}} = \frac{{0.1}}{{0.42}} = \frac{5}{{21}}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 13. probability→13. probability — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The corner points of the feasible region determined by the following system of linear inequalities:

2x + y ≤ 10, x + 3y ≤ 15, x, y ≥ 0 are (0, 0), (5, 0), (3, 4) and (0, 5).

Let Z = px + qy, where p.q > 0.

Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is:

  1. P = q
  2. p = 2q
  3. p = 3q
  4. q = 3q
→
Let $S=\left\{(x, y) \in R \times R : x \geq 0, y \geq 0, y^2 \leq 4 x, y^2 \leq 12-2 x\right.$ and $\left.3 y+\sqrt{8} x \leq 5 \sqrt{8}\right\}$. If the area of the region $S$ is $\alpha \sqrt{2}$, then $\alpha$ is equal to
→
$\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&{1 + x}&1\\1&1&{1 + y}\end{array}\,} \right| = $
→
Choose the correct answer from the given four options.

The value of the expression $\tan\Big(\frac{1}{2}\cos^{-1}\frac{2}{\sqrt{5}}\Big)$ is:

  1. $2+\sqrt{5}$

  2. $\sqrt{5}-2$

  3. $\frac{\sqrt{5}+2}{2}$

  4. $5+\sqrt{2}$

Hint: $\bigg[\tan\frac{\theta}{2}=\sqrt{\frac{1-\cos\theta}{1+\cos\theta}}\bigg]$

→
The distance of the line $\vec{\text{r}}=2\hat{\text{i}}-2\hat{\text{j}}+3\hat{\text{k}}+\lambda(\hat{\text{i}}-\hat{\text{j}}+4\hat{\text{k}})$ from the plane $\vec{\text{r}}.(\hat{\text{i}}+5\hat{\text{j}}+\hat{\text{k}})=5$ is:

  1. $\frac{5}{3\sqrt{3}}$

  2. $\frac{10}{3\sqrt{3}}$

  3. $\frac{25}{3\sqrt{3}}$

  4. $\text{None of these}$

→
Assume that in a family, each chold is equally likely to be a boy or a girl. A family with tree cgildren is chosen at random. Tere probability that the eldest child is a girl given that the family has at least oe girl.
→
If $y = {x^2}{e^{mx}}$, where $m$ is a constant, then ${{{d^3}y} \over {d{x^3}}} = $
→
The value of $\int_{\,0}^{\,\pi /2} {{{\left( {\sqrt {\sin \theta } \cos \theta } \right)}^3}d\theta } $ is
→
Let $\lambda \in R , \vec{a}=\lambda \hat{i}+2 \hat{j}-3 \hat{k}, \vec{b}=\hat{i}-\lambda \hat{j}+2 \hat{k}$ If $((\vec{a}+\vec{b}) \times(\vec{a} \times \vec{b})) \times(\vec{a}-\vec{b})=8 \hat{i}-40 \hat{j}-24 \hat{k}$, then $|\lambda(\vec{a}+\vec{b}) \times(\vec{a}-\vec{b})|^2$ is equal to
→
$\int_0^{\pi /3} {\cos 3x\,dx = } $
→