MCQ
For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1\,kg$, the angular frequency is $\omega_1$. When the mass block is $2\,kg$ the angular frequency is $\omega_2$. The ratio $\omega_2 / \omega_1$ is
  • A
    $\sqrt{2}$
  • $\frac{1}{\sqrt{2}}$
  • C
    $2$
  • D
    $\frac{1}{2}$

Answer

Correct option: B.
$\frac{1}{\sqrt{2}}$
b
$\omega=\sqrt{\frac{ k }{ m }}$

$\frac{\omega_2}{\omega_1}=\sqrt{\frac{ m _1}{ m _2}}=\sqrt{\frac{1}{2}}$

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