MCQ
For a thermodynamic process $\delta Q = -50$ $calorie$ and $W = -20$ $calorie$ . If the initial internal energy is $-30$ $calorie$ then final internal energy will be ....... $calorie$
- A$191.20$
- ✓$-60$
- C$100$
- D$-100$
✓
Answer
Correct option: B.
$-60$
b
$\delta \mathrm{Q}=\mathrm{W}+\delta \mathrm{U}$
$\delta \mathrm{Q}=\mathrm{W}+\delta \mathrm{U}$
$-50=-20+\left(U_{t}-U_{1}\right)$
$\mathrm{U}_{\mathrm{f}}-(-30)=-30$
$\mathrm{U}_{\mathrm{f}}=-60 \mathrm{Cal}$
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