For a transistor, in a common emitter arrangement, the alternatin… - Vidyadip

MCQ

For a transistor, in a common emitter arrangement, the alternating current gain $b$ is given by

✓
$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{VC}}$
B
$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{C}}}\right)_{\mathrm{VC}}$
C
$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{E}}}\right)_{\mathrm{VC}}$
D
$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{E}}}{\Delta \mathrm{I}_{\mathrm{C}}}\right)_{\mathrm{VC}}$

✓

Answer

Correct option: A.

$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{VC}}$

$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{VC}}$

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