MCQ
For adiabatic processes $\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)$
- A${P^\gamma }V$ = constant
- B${T^\gamma }V$= constant
- ✓$T{V^{\gamma - 1}}$ =constant
- D$T{V^\gamma }$ = constant
✓
Answer
Correct option: C.
$T{V^{\gamma - 1}}$ =constant
c
(c)In adiabatic process $P{V^\gamma } = $constant
==> $\left( {\frac{{RT}}{V}} \right).{V^\gamma } = $constant ==> $T{V^{\gamma - 1}}$= constant
(c)In adiabatic process $P{V^\gamma } = $constant
==> $\left( {\frac{{RT}}{V}} \right).{V^\gamma } = $constant ==> $T{V^{\gamma - 1}}$= constant
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