MCQ
For high frequency, a capacitor offers
- AMore reactance
- ✓Less reactance
- CZero reactance
- DInfinite reactance
✓
Answer
Correct option: B.
Less reactance
b
${X_C} = \frac{1}{{2\pi \nu C}}\, \Rightarrow {X_C} \propto \frac{1}{\nu }$
${X_C} = \frac{1}{{2\pi \nu C}}\, \Rightarrow {X_C} \propto \frac{1}{\nu }$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A square coil of area $10^{-2} m^2$ is kept perpendicular in a magnetic field of intensity $10^3 Wb / m ^2$. The magnitude of magnetic flux passing through the square is :
→A plane electromagnetic wave travelling along the $X$-direction has a wavelength of $3\ mm$ . The variation in the electric field occurs in the $Y$-direction with an amplitude $66\ Vm^{-1}$. The equations for the electric and magnetic fields as a function of $x$ and $t$ are respectively :-
→A varying current at the rate of 3 A/s in a coil generates an e.m.f. of 8 mV in a nearby coil. The mutual inductance of the two coils is
For the $L -R$ circuit shown in figure the phase angle......$^o$ if frequency is $f = 100/\pi $
→An electron oscillating with a frequency of $3 \times 10^6 Hz$, would generate:
→A $10\, \Omega, 20 \; mH$ coil carrying constant current is connected to a battery of $20 \; V$ through a switch is opened current becomes zero in $100 \; \mu s$. The average emf induced in the coil is $\dots \; V$.
→The isotope ${ }_5^{12} \mathrm{~B}$ having a mass $12.014 \mathrm{u}$ undergoes $\beta$-decay to ${ }_6^{12} \mathrm{C} .{ }_6^{12 .}$ has an excited state of the nucleus $\left({ }_6^{12} \mathrm{C}^*\right)$ at $4.041 \mathrm{MeV}$ above its ground state. If ${ }_5^{12} \mathrm{~F}$ decays to ${ }_6^{12} \mathrm{C}^*$, the maximum kinetic energy of the $\beta$-particle in units of $\mathrm{MeV}$ is ( $1 \mathrm{u}=931.5 \mathrm{MeV} / c^2$, where $c$ is the speed of light in vacuum).
→A potentiometer $PQ$ is set up to compare two resistances as shown in the figure. The ameter $A$ in the circuit reads $1.0\, A$ when two way key $K_3$ is open. The balance point is at a length $l_1\, cm$ from $P$ when two way key $K_3$ is plugged in between $2$ and $1$ , while the balance point is at a length $l_2\, cm$ from $P$ when key $K_3$ is plugged in between $3$ and $1$ . The ratio of two resistances $\frac{{{R_1}}}{{{R_2}}}$ is found to be
→A current of $0.1 A$ circulates around a coil of $100$ turns and having a radius equal to $5\ cm$. The magnetic field set up at the centre of the coil is $(m_0= 4π × 10^{-7}$ weber/amp-metre$)$
→Two ideal slits $\mathrm{S}_1$ and $\mathrm{S}_2$ are at a distance d apart, and illuminated by light of wavelength λ passing through an ideal source slit S placed on the line through $\mathrm{S}_2$ as shown. The distance between the planes of slits and the source slit is D. A screen is held at a distance D from the plane of the slits. The minimum value of d for which there is darkness at O is
→