MCQ
For $n^{th}$ order reaction where $(n < 1)$
  • A
    ${t_{100\% }} = \frac{1}{{n-1}}\,\frac{{A_0^{n - 1}}}{K}$
  • ${t_{100\% }} = \frac{1}{{1-n}}\,\frac{{\left[ A \right]_0^{1 - n}}}{K}$
  • C
    ${t_{100\% }} = \frac{1}{n}\,\frac{{\left[ A \right]_0^{n - 1}}}{K}$
  • D
    ${t_{100\% }} = \frac{1}{{1 - n}}\,\frac{{A_0^n}}{K}$

Answer

Correct option: B.
${t_{100\% }} = \frac{1}{{1-n}}\,\frac{{\left[ A \right]_0^{1 - n}}}{K}$
b

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