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Equilibrium — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryEquilibrium3 Marks
Question
For the reaction : $\text{N}_2\text{(g)}+\text{3H}_2\text{(g)}\rightleftharpoons\text{2NH}_3\text{(g)}$ Equilibrium constant $\text{K}_\text{c}=\frac{[\text{NH}_3]^2}{[\text{N}_2][\text{H}_2]^3}$ Some reactions are written below in Column I and their equilibrium constants in terms of $\text{K}_\text{c}$ are written in Column II. Match the following reactions with the corresponding equilibrium constant.
Column I (Reaction) Column II (Equilibrium constant)
i. $2\text{N}_2\text{(g)}+\text{6H}_2\text{(g)}\rightleftharpoons\text{4NH}_3\text{(g)}$ a. $2\text{K}_\text{c}$
ii. $2\text{NH}_3\text{(g)}\rightleftharpoons\text{N}_2\text{(g)}+\text{3H}_2\text{(g)}$ b. $\text{K}_\text{c}^\frac{1}{2}$
iii. $\frac{1}{2}\text{N}_2\text{(g)}+\frac{3}{2}\text{H}_2\text{(g)}\rightleftharpoons\text{NH}_3\text{(g)}$ c. $\frac{1}{\text{K}_\text{c}}$
    d. $\text{K}_\text{c}^2$
✓

Answer

Column I (Reaction) Column II (Equilibrium constant)
i. $2\text{N}_2\text{(g)}+\text{6H}_2\text{(g)}\rightleftharpoons\text{4NH}_3\text{(g)}$ d. $\text{K}_\text{c}^2$
ii. $2\text{NH}_3\text{(g)}\rightleftharpoons\text{N}_2\text{(g)}+\text{3H}_2\text{(g)}$ c. $\frac{1}{\text{K}_\text{c}}$
iii. $\frac{1}{2}\text{N}_2\text{(g)}+\frac{3}{2}\text{H}_2\text{(g)}\rightleftharpoons\text{NH}_3\text{(g)}$ b. $\text{K}_\text{c}^\frac{1}{2}$

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