For what value of $R$ the net resistance of the circuit will be $18\, ohms$ ............... $\Omega$
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(c) $R_{e q}=10+\frac{16 R}{16+R}$
$18=10+\frac{16 R}{16+R} \Rightarrow 8=\frac{16 R}{16+R}$
$128+8 R=16 R \Rightarrow 8 R=128$
$R=16 \Omega$
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