In the circuit shown below the resistance of the galvanometer is $20\, \Omega$ . In which case of the following alternatives are the currents arranged strictly in the decreasing order
Medium
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(b) $i \propto \frac{1}{R}$
$P+Q>R+S$
$i=i_{1}+i_{2}$
$i>i_{2}>i_{1}>i_{g}$
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