Forty electric bulbs are connected in series across a $220\, V$ supply. After one bulb is fused, the remaining $39$ are connected again in series across the same supply. The illumination will be
AMore with $40$ bulbs than with $39$
BMore with $39$ bulbs than with $40$
C
Equal in both the cases
DIn the ratio of ${49^2}:{39^2}$
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BMore with $39$ bulbs than with $40$
b (b) When $1$ bulb fuses, the total resistance of the circuit decreases hence the current increases. Since $P = {i^2}R$, therefore illumination increases.
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