Question
From the following cumulative frequency table , find :
Median
Lower quartile
Upper quaetile
 
Marks (less than ) 10 20 30 40 50 60 70 80 90 100
Cumulative frequency 5 24 37 40 42 48 70 77 79 80

Answer

Marks (less than) Cumulative frequency
10 5
20 24
30 37
40 40
50 42
60 48
70 70
80 77
90 79
100 80
Number of terms= 80
Median= $40^{th}$term

Median= Through $40^{th}$ term mark draw a line parallel to the x-axis which meets the curve at A. from A, Draw a perpendiculer to axis which meets it at B.
Value of B is the median - 40
Lower quartile $(Q_1) = 20^{th}$ term=18
Upeer Quartile $(Q_3) = 60^{th}$ term = 66

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