From the following which is a second order reaction - Vidyadip

MCQ

From the following which is a second order reaction

A
$K = 5.47 \times {10^{ - 4}}\,{\sec ^{ - 1}}$
B
$K = 3.9 \times {10^{ - 3}}\,{\rm{mole}}\,\,{\rm{lit}}\,\,{\sec ^{ - 1}}$
✓
$K = 3.94 \times {10^{ - 4}}\,{\rm{lit}}\,\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}\,\,{\sec ^{ - 1}}$
D
$K = 3.98 \times {10^{ - 5}}{\rm{lit}}\,\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 2}}}}\,\,{\sec ^{ - 1}}$

✓

Answer

Correct option: C.

$K = 3.94 \times {10^{ - 4}}\,{\rm{lit}}\,\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}\,\,{\sec ^{ - 1}}$

c
(c) Unit of rate constant for second order reaction is $mo{l^{ - 1}}litre\,\,tim{e^{ - 1}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 3. Chemical kinetics→3. Chemical kinetics — all question types→Chemistry STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The molar freezing point constant for water is ${1.86\,^o}C\,mol{e^{ - 1}}$. If $ 342\,gm$ of canesugar $({C_{12}}{H_{22}}{O_{11}})$ are dissolved in $1000\,gm$ of water, the solution will freeze at ............ $^oC$.

The freezing point of a $0.05\,molal$ solution of a non electrolyte in water is ( $K_f = \,1.86\,K\,molality^{-1}$ )

Below are two statements. One is labeled as Assertion $(A)$ and the other as Reason $(R):$

Assertion $(A):$ $\mathrm{H}_2 \mathrm{Te}$ is more acidic than $\mathrm{H}_2 \mathrm{~S}$.

Reason $(R):$ The bond dissociation enthalpy of $\mathrm{H}_2 \mathrm{Te}$ is less than that of $\mathrm{H}_2 \mathrm{~S}$.

In the context of the above statements, choose the correct answer from the following options:

The amount of ${K_2}C{r_2}{O_7}$ (eq. wt. $ 49.04$) required to prepare $100\,ml$ of its $0.05\,N$ solution is ........ $g$

Monazite is an ore of:

$Ph-N{{H}_{2}}\xrightarrow{C{{H}_{3}}Cl\,(2mole)}(A)\xrightarrow{Ph-\overset{\oplus }{\mathop{{{N}_{2}}}}\,\overline{Cl}}\underset{Butter\,yellow}{\mathop{(B)}}\,\,(major)$

Product of the above reaction is

Compound $A$ was treated with a large excess of $CH_3MgBr$. The resulting product was exposed to $POCl_3$ /pyridine to give compound $B$, as one of many products

Which of the following compounds can be $A$ ?

The solubility of a gas in water depends on

The correct description of the product in the above reaction is

$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}OC{H_3}} \\
| \\
{\mathop {C{H_3}CHBr}\limits_{(R)} }
\end{array}$ $\xrightarrow[{acetone}]{{NaCN}}$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}OC{H_3}} \\
| \\
{\mathop {C{H_3}CHCN}\limits }
\end{array}$

Which ine of the following statement about lanthanides is false?