Question
Give the feature of prohibition by explaining the logical form of ‘~’.
| 1 | 2 | |
| p | ~ p | |
| 1 | T | F |
| 2 | F | T |
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| $A \rightarrow B$ |
| $(A\ \&\ B) \rightarrow C$ |
| $A$ |
| $\therefore (A\ \&\ B)\ \&\ (A\ \&\ C)$ |
| $(R\ \&\ S)\ v\ P$ |
| $P\ \rightarrow\ Q$ |
| $T\ v\ (R\ \&\ S)\ \rightarrow\ W ]$ |
| $S\ \&\ \sim\ T$ |
| $[S\ \&\ (W\ v\ Q)]\ v\ \sim\ P$ |
| $(P\ \&\ Q) \rightarrow R$ |
| $R \rightarrow (H \rightarrow G)$ |
| $H\ \&\ K$ |
| $P\ \&\ Q$ |
| $\therefore (G\ v\ I)\ \&\ H$ |
| $R\rightarrow (S\ \&\ T)$ |
| $P\ v\ \sim (S\ \&\ T)$ |
| $Q\ \&\ \sim P$ |
| $\sim R\rightarrow (X\ \&\ Y)$ |
| $Q\ \&\ X$ |
| $(P\ v\ R)\ \rightarrow (S\ v\ T)$ |
| $\sim M\ \&\ \sim N$ |
| $N\ v \sim (S\ v\ T)$ |
| $H \rightarrow (P\ v\ R)$ |
| $[\sim H\ \&\ \sim (P\ v\ R)]\ v\ S$ |