Now work done $=m \times$ potential difference.
Thus work done for a distance of $4 m$ for a mass $5 k g, W=\frac{4}{20} \times 2 \times 5$
$\Longrightarrow W=2 J$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
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List I |
List II |
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$(i)$ Curie |
$(A)$ $ML{T^{ - 2}}$ |
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$(ii)$ Light year |
$(B)$ $M$ |
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$(iii)$ Dielectric strength |
$(C)$ Dimensionless |
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$(iv)$ Atomic weight |
$(D)$ $T$ |
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$(v)$ Decibel |
$(E)$ $M{L^2}{T^{ - 2}}$ |
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$(F)$ $M{T^{ - 3}}$ |
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$(G)$ ${T^{ - 1}}$ |
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$(H)$ $L$ |
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$(I)$ $ML{T^{ - 3}}{I^{ - 1}}$ |
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$(J)$ $L{T^{ - 1}}$ |
An astronaut in an orbiting space station above the Earth experiences weightlessness. and
$STATEMENT-2$
An object moving around the Earth under the influence of Earth's gravitational force is in a state of 'free-fall'.
| S.No. | $MS\;(cm)$ | $VS$ divisions |
| $(1)$ | $0.5$ | $8$ |
| $(2)$ | $0.5$ | $4$ |
| $(3)$ | $0.5$ | $6$ |
If the zero error is $- 0.03\,cm,$ then mean corrected diameter is ........... $cm$