MCQ
Groups that can show both +M and -M effect:
- Avinyl
- Bphenyl
- C-NO
- DAll of these
Explanation:
CH2 = CH− and phenyl both contain double bonds, Since we know -NO, C=C both can show +M and -M effect both hence all of the above options are correct.
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$(R = 0.083\, L\, bar\, K^{-1} \,mol^{-1})$
$HC \equiv CH\,\xrightarrow[{H{g^{2 + }}}]{{{H_2}S{O_4}}}\,'P'$
Product $'P'$ will not give