MCQ
${H_2}S$ is more acidic than ${H_2}O$, due to
- A$O$ is more electronegative than $S$
- ✓$O - H$ bond is stronger than $S - H$ bond
- C$O - H$ bond is weaker than $S - H$ bond
- DNone of these
${H_2}O < {H_2}S < {H_2}Se < {H_2}Te$
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(Rounded off to the nearest integer) [Given : Atomic weight in $g\, mol ^{-1}- Na : 23$; $N : 14 ; O : 16]$
$H _{2}+\frac{1}{2} O _{2} \rightarrow H _{2} O , \cdots \cdots( ii )$ $\Delta H =-\,287.3 \,kJ\,mol ^{-1}$
$2 CO _{2}+3 H _{2} O \rightarrow C _{2} H _{5} OH +3 O _{2} \cdots \cdots ( iii )$; $ \Delta H =1366.8 \,kJ\,mol ^{-1}$
Find the standard enthalpy of formation of $C _{2} H _{5} OH (1)$
