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$A$ and $B$ are :
$CH_3CH_2CH_2Br + NaCN \to $$CH_3CH_2CH_2CN+ NaBr$
This reaction will be the fastest in
Statement $(I)$ : In the Lanthanoids, the formation of $\mathrm{Ce}^{+4}$ is favoured by its noble gas configuration.
Statement $(II)$ : $\mathrm{Ce}^{+4}$ is a strong oxidant reverting to the common $+3$ state.
In the light of the above statements, choose the most appropriate answer from the options given below:
$E^o_{Cr^{3+}/Cr} =-0.74\, V,\,$ $E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V$
$E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:$ $E^o_{Cl/Cl^-} =1.36\,V$
Based on the data given above, strongest oxidising agent will be :
$2N{H_3}(g)\xrightarrow[{Pt\,catalyst}]{{1130\,K}}{N_2}(g) + 3{H_2}(g)$
Choose the option which is not true with respect to the reaction, from the choices given below :-
$A \to B$ ${K_1} = {10^{15}}{e^{ - 25000/8.314\,T}}$
$C \to D$ ${K_2} = {10^{14}}{e^{ - 15000/8.314\,T}}$