MCQ
$HNO_3 + P_4O_{10} \to 4HPO_3 + X$ . $X$ is
- ✓$N_2O_5$
- B$NO_2$
- C$NO$
- D$N_2O_3$
$4 HNO _3+ P _4 O _{10} \rightarrow 4 HPO _3+2 N _2 O _5$
The product, $x$ is dinitrogen pentaoxide $\left( N _2 O _5\right)$.
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