Question
How many bricks will be required to construct a wall $13.5\ m$ long; 6m high and $22.5\ cm$ thick if each brick measures $(27\ cm \times 12.5\ cm \times 9\ cm)$?
✓
Answer
Length of the wall $= (13.5 \times 100)cm = 1350\ cm$
Breadth of the wall $= 22.5\ cm$
Height of the wall $= (6 \times 100)cm = 600\ cm$
Volume of the wall$ = (1350 \times 22.5 \times 600)\ cm^3$
Volume of each brick $= (27 \times 12.5 \times 9)\ cm^3$
Number of brick required $=\frac{\text{Volume of the wall }}{\text{Volume of $1$ brick }}$
$=\Big(\frac{1350\times22.5\times600}{27\times12.5\times9}\Big)$
$=6000$
Breadth of the wall $= 22.5\ cm$
Height of the wall $= (6 \times 100)cm = 600\ cm$
Volume of the wall$ = (1350 \times 22.5 \times 600)\ cm^3$
Volume of each brick $= (27 \times 12.5 \times 9)\ cm^3$
Number of brick required $=\frac{\text{Volume of the wall }}{\text{Volume of $1$ brick }}$
$=\Big(\frac{1350\times22.5\times600}{27\times12.5\times9}\Big)$
$=6000$
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