MCQ
How many $H^+$ ions are present in $2\, mL$ of a solution whose $pH$ is $13$ ?
- A${10^{ - 16}}$
- ✓$12.04 \times {10^7}$
- C$6.02 \times {10^7}$
- D$12.04 \times {10^{13}}$
Moles $=$ Molarity $\times V$ inlitre
$=\quad 10^{-13} \times \frac{2}{1000}$
$=\quad 10-13 \times 2 \times 10^{-3}$
$=\quad 2 \times 10^{-16}$
no. of $H^+$ ions $=2 \times 10^{-16} \times 6.023 \times 10^{23}$
$=12.046 \times 10^7$
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$\left( i \right)\,2F{e_2}{O_3}\left( s \right) \to 4Fe\left( s \right) + 3{O_2}\left( g \right)$
${\Delta _r}{G^o} = + 1487.0\,kJ\,mo{l^{ - 1}}$
$\left( {ii} \right)\,2CO\left( g \right) + {O_2}(g) \to 2C{O_2}\left( g \right)$
${\Delta _r}{G^o} = - 514.4\,kJ\,mo{l^{ - 1}}$
Free energy change, $\Delta_rG^o$ for the reaction
$\,2F{e_2}{O_3}\left( s \right) + 6CO\left( g \right) \to 4Fe\left( s \right) + 6C{O_2}\left( g \right)$ will be .....$kJ\, mol^{-1}$