MCQ
Hybridisation state of chlorine in $Cl{F_3}$ is
- A$s{p^3}$
- ✓$s{p^3}d$
- C$s{p^3}{d^2}$
- D$s{p^3}{d^3}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$2MnO_4^ - + 5{C_2}O_4^ - + 16{H^ + } \to 2M{n^{ + + }} + 10C{O_2} + 8{H_2}O$
Here $20\, mL$ of $0.1\, M\, KMnO_4$ is equivalent to
$\frac{1}{2}\,{P_4}(s)\,\, + \,\,3C{l_2}(g)\, \to \,2PC{l_3}(\ell )\,\,\,\,\,\Delta H\, = \, - \,635\,\,kJ$
$PCl_3 (\ell )\,+\,Cl_2(g)\,\to \,PCl_5(s) \,\,\,\,\Delta H\, =\, -\,137\,kJ$.....$kJ$

