$I-V$ characteristic of a copper wire of length $L$ and area of cross-section $A$  is shown in figure. The slope of the curve becomes
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(d) Slope of $V-i$ curve $ = R\,\left( { = \frac{{\rho l}}{A}} \right)$. But in given curve axis of $i$ and $V$ are interchanged. So slope of given curve $ = \frac{1}{R}\left( { = \frac{A}{{\rho l}}} \right)$ i.e. with the increase in length of the wire. Slope of the curve will decrease.
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