$(I)$ Only compounds with chiral centers can be optically active
$(II)$ Absence of elements of symmetry is the reason for a molecule's optical activity
$(II)$ All organic compounds contain carbon & hydrogen
$(IV)$ Different cannonical forms of a molecule represent the actual structures of a molecule which has resonace in it
$(II)$ Optical activity is due to different rotation of plane polarised light by the moleucle. Absence of symmetry is not the reason for optical activity.
$(III)$ Not all organic compounds may contain hydrogen
$(IV)$ Cannonical forms are not a ctual structures; they are the most suitable representations of the molecule
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| $Ion$ | $Z ^{ n +}$ | $Z ^{ P +}$ | $Z ^{ n +}$ | $Z ^{ m +}$ | $Z ^{ m +}$ |
| $\lambda^0\left( S cm ^2 mol ^{-1}\right)$ | $50.0$ | $25.0$ | $100.0$ | $80.0$ | $100.0$ |
$\lambda^0$ is the limiting molar conductivity of ions
The plot of molar conductivity $(4)$ of $Z _{ m } X _{ n } v s c ^{1 / 2}$ is given below.
| LIST-$I$ | LIST-$I$ |
| $A$.Glucose/NaHCO3/$\Delta$ | $I$.Gluconic acid |
| $B$.Glucose/HNO3 | $II$. No reaction |
| $C$.Glucose/HI/ $\Delta$ | $III$. n-hexane |
| $D$. Glucose/Bromine [water] | $IV$. Saccharic acid |
Choose the correct answer from the options given below:
$\mathrm{C}_{7} \mathrm{H}_{8} \stackrel{3 \mathrm{Cl}_{2} / \Delta}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{Br}_{2} / \mathrm{Fe}}{\rightarrow} \mathrm{B} \stackrel{\mathrm{Zn} / \mathrm{HCl}}{\rightarrow} \mathrm{C}$
The product '$C$' is
$(a)$ Peroxide ion as well as dioxygen molecule both are paramagnetic species
$(b)$ In set of isomers, $[Cr(H_2O)_6]Cl_3$ and $[CrCl(H_2O) _5]Cl_2 . H_2O,$ both compounds can easily loose water molecule on treatment with cone. $H_2SO_4$
$(c)$ During transformation $NO \to NO^+$ , bond length and magnetic behaviour decreases
$(d)$ An ether is more volatile than alcohol both having same molecular formula