MCQ
Identify the reaction from following having top position in $EMF$ series (Std. red. potential) according to their electrode potential at $298 \;K$.
  • A
    $K ^{+}+1 e ^{-} \rightarrow K _{( s )}$
  • B
    $Mg ^{2+}+2 e ^{-} \rightarrow Mg _{( s )}$
  • C
    $Fe ^{2+}+2 e ^{-} \rightarrow Fe _{( s )}$
  • $Au ^{3+}+3 e ^{-} \rightarrow Au _{( s )}$

Answer

Correct option: D.
$Au ^{3+}+3 e ^{-} \rightarrow Au _{( s )}$
d
$\begin{array}{ll}A u^{3+}+3 e^{-} \rightarrow A u(s) & E^{0}=1.40 \vee \\ F e^{2+}+2 e^{-} \rightarrow F e(s) & E^{0}=-0.44 v \\ M g^{2+}+2 e^{-} \rightarrow M g(s) & E^{0}=-2.36 v \\ K^{+}+1 e^{-} \rightarrow K(s) & E^{0}=-2.93 V\end{array}$

As per electrochemical series, $Au ^{3+}$ occupies. the top position.

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$\underset{(A)}{\mathop{\begin{matrix}
   \,\,\,\,\,Ph\,\,\,\,C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,|\,\,  \\
   Ph-C-C-C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,|\,\,\,  \\
   \,OH\,\,\,OH  \\
\end{matrix}}}\,+\underset{(B)}{\mathop{\begin{matrix}
   \,\,\,\,Ph\,\,\,Et  \\
   \,\,|\,\,\,\,\,\,\,\,\,|  \\
   Ph-C-C-Et  \\
   \,\,|\,\,\,\,\,\,\,\,\,|  \\
   \,\,\,\,\,OH\,\,OH  \\
\end{matrix}}}\,\xrightarrow{{{H}_{2}}S{{O}_{4}}}$

 

$(p)$ $\begin{matrix}
   Ph\,\,\,\,\,O\,  \\
   |\,\,\,\,\,\,\,\,||\,\,  \\
   Ph-C-C-C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}\,\,\,\,\,\,\,\,  \\
\end{matrix}$                                $(q)$ $\begin{matrix}
   \,Ph\,\,\,\,\,O\,  \\
   \,\,|\,\,\,\,\,\,\,\,||  \\
   Ph-C-C-Et  \\
   |\,\,\,\,\,\,\,\,\,\,  \\
   Et\,\,\,\,\,\,\,\,\,\,  \\
\end{matrix}$

$(r)$ $\begin{matrix}
   \,Ph\,\,\,\,\,O\,  \\
   |\,\,\,\,\,\,\,\,\,\,||\,  \\
   Ph-C-C-C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   Et\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
\end{matrix}$                             $(s)$ $\begin{matrix}
   \,\,\,Ph\,\,\,\,\,O\,  \\
   \,\,|\,\,\,\,\,\,\,\,||  \\
   Ph-C-C-Et  \\
   |\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}\,\,\,\,  \\
\end{matrix}$

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