MCQ
In the reaction shown below, the major product$(s)$ formed is/are


- ✓

- B

- C

- D







since $- CH _2- NH _2$ is more basic.
The resulting amide will fail to react further. Had it been possible, imied formation would have occured at both the sites.
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$(I)$ $CO_2$ $(II)$ $Br_2$ $(III)$ $SnCl_2$ $(IV)$ $HF$ $(V)$ $NMe_3$