- ASalicylic acid’s a monobasic acid
- BMethyl salicylate is an ester
- CSalicylic acid gives violet colour with neutral ferric chloride as well as brisk effervescence with sodium bicarbonate
- ✓Methyl salicylate does not occur in natural oils
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$H{_2(g)} + 2ICl_{(g)} \to 2HCl_{(g)} + I_{2(g)}$
This reaction is of first order with respect to $H_{2(g)}$ and $ICl_{(g)}$ , following mechanisms were proposed
Mechanism $A$ :
$H{_2(g)} + 2ICl_{(g)} \to 2HCl_{(g)} + I_{2(g)}$
Mechanism $B$ :
$H_{2(g)} + ICl_{(g)} \to HCl_{(g)} + HI_{(g)}$ ; Slow
$HI_{(g)} + ICl_{(g)} \to HCl_{(g)} + I_{2(g)}$ ; Fast
Which of the above mechanism $(s)$ can be consistent with the given information about the reaction
$(i)\,\, Cl^-$ can give up an electron more easily than $F^-$
$(ii) \,\,Cl^-$ is a better reducing agent than $F^-$
$(iii)\,\, Cl^-$ is smaller in size than $F^-$
$(iv)\,\, F^-$ can be oxidized more readily than $Cl^-$
$(a)$ saline hydrides produce $H_2$ gas when reacted with $H_2O.$
$(b)$ reaction of $LiAH_4$ with $BF_3$ leads to $B_2H_6.$
$(c)$ $PH_3$ and $CH_4$ are electron - rich and electron-precise hydrides, respectively.
$(d)$ $HF$ and $CH_4$ are called as molecular hydrides.

$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
This reaction is of first order with respect to $H_{2(g)}$ and $ICl_{(g)},$
following mechanisms were proposed.
Mechanism $A\, :$
$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
Mechanism $B\, :$
$H_{2(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + HI_{(g)}\, ;$ slow
$HI_{(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + I_{2(g)} \,;$ fast
Which of the above mechanism(s) can beconsistent with the given information about the reaction ?