MCQ
If $4.0 \,gm $ $NaOH$ is present in $1$ litre solution, then its $pH$ will be
- A$6$
- ✓$13$
- C$18$
- D$24$
$[O{H^ - }] = {10^{ - 1}}M$, $[{H^ + }] = {10^{ - 13}}M$, $pH = 13$
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$B.E(N -N) = 159\, kJ\, mol^{-1}$,
$B.E(H -H) = 436\, kJ\, mol^{-1}$
$B.E.(N \equiv N) = 941\, kJ\, mol^{-1}$,
$B.E(N -H) = 398\, kJ\, mol^{-1}\, .......\,kJ\, mol^{-1}$