Question
If A = [1] , then A is:
  1. Zero matrix
  2. SIngular matrix
  3. Non - singular matrix
  4. Data insufficient

Answer

  1. Non - singular matrix

Solution:

$\text{A} = \big[1\big] $ is an identity matrix with order $1\times1.|\text{A}|\neq0$

So A is nonsingular.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $y=\frac{\ln x}{x}$, then the value of $y^{\prime \prime}(e)$ is
The order and degree of the differential equation $x{\rm{ }}{\left( {\frac{{dy}}{{dx}}} \right)^3} + 2\,{\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^2} + 3y + x = 0$ are respectively
Mark the correct alternative in the following question:
Suppose a random variable X follows the binomial distribution with parameters n and p, where 0 < p < 1. If $\frac{\text{P(X = r})}{\text{P(X = n} -\text{r})}$ is independent of n and r, then p equals:
  1. $\frac{1}{2}$
  2. $\frac{1}{3}$
  3. $\frac{1}{5}$
  4. $\frac{1}{7}$
If $\vec{\text{a}}.\vec{\text{b}}=\vec{\text{a}}.\vec{\text{c}}$ and $\vec{\text{a}}\times\vec{\text{b}}=\vec{\text{a}}\times\vec{\text{c}}.\vec{\text{a}}\neq0,$ then:
  1. $\vec{\text{b}}=\vec{\text{c}}$
  2. $\vec{\text{b}}=\vec{0}$
  3. $\vec{\text{b}}+\vec{\text{c}}=\vec{0}$
  4. $\text{None of these}$
The order of differential equation $\left(\frac{d^3 y}{d x^3}\right)^4+\left(\frac{d^2 y}{d x^2}\right)^2+\sin \left(\frac{d y}{d x}\right)+1=0$ is ___________ .
Let R be the relation in the set N given by $R =\{(a, b): a=b-2, b>6\}$. Then choose the correct option from the following.
Let $f(x) = x^3 + px + 1$ and consider following three statements Then

$(i)$ for $p \geqslant  0$ , $f(x) = 0$ has one negative root and $f(x)$ is monotonic

$(ii)$ for $-1 < p < 0$ , $f(x)$ = $0$ has one negative root and $f(x)$ is nonmonotonic
$(iii)$ for $p < 0$ , $f(x)$ = $0$ has three real and distinct roots.

$\int_0^{\pi /6} {(2 + 3{x^2})\cos 3x\,dx = } $
Let $f(x)=3 \sin ^{4} x+10 \sin ^{3} x+6 \sin ^{2} x-3, x \in\left[-\frac{\pi}{6}, \frac{\pi}{2}\right] .$ Then, $f$ is $.....$
If $f(x) = \frac{{\alpha \,x}}{{x + 1}},\;x \ne - 1$. Then, for what value of $\alpha $ is $f(f(x)) = x$