MCQ
If $A = \left[ {\begin{array}{*{20}{c}}1&0&1\\2&1&0\\3&2&1\end{array}} \right],$then $\det A$=
  • $2$
  • B
    $3$
  • C
    $4$
  • D
    $5$

Answer

Correct option: A.
$2$
a
(a) $|A| = \left| {\,\begin{array}{*{20}{c}}1&0&1\\2&1&0\\3&2&1\end{array}\,} \right|$ = $1(1 - 0) + 0 + 1(4 - 3)$ = $2.$

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