If a particle under S.H.M. has time period 0.1 sec and amplitude $2 \times 10^{-3}$. It has maximum velocity
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(a)${v_{\max }} = a\omega = \frac{{a \times 2\pi }}{T} = \frac{{2 \times {{10}^{ - 3}} \times 2\pi }}{{0.1}} = \frac{\pi }{{25}}m/s$
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