The bob of simple pendulum having length $l$, is displaced from mean position to an angular position $\theta$ with respect to vertical. If it is released, then velocity of bob at lowest position
A$\sqrt{2 g l \cos \theta}$
B$\sqrt {2gl(1 + \cos \theta )} $
C$\sqrt {2gl(1 - \cos \theta )} $
D$\sqrt{2 gl}$
AIPMT 2000, Medium
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C$\sqrt {2gl(1 - \cos \theta )} $
c (c)If suppose bob rises up to a height h as shown then after releasing potential energy at extreme position becomes kinetic energy of mean position
$ \Rightarrow mgh = \frac{1}{2}mv_{\max }^2$
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