Question
If a point $'C'$ lies between two points $A$ and $B$ such that $AC = BC,$ then prove that $AC =\frac{1}{2}AB$. Explain by drawing the figure.
✓
Answer
Given, $AC = BC$
$AC + AC = BC + AC . . . . [AC$ are added to both the side$]$
$2AC = AB . . . . [BC + AC$ coincides with $AB]$
$\therefore AC = \frac{1}{2}AB$
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