MCQ
If ${(a \times b)^2} + {(a\,\,.\,\,b)^2} = 144$ and $|a|\, = 4,$ then $|b|\, = $
  • A
    $16$
  • B
    $8$
  • $3$
  • D
    $12$

Answer

Correct option: C.
$3$
c
(c) We know that ${(a \times b)^2} + {(a\,.\,b)^2} = \,|a{|^2}|b{|^2}$

$\therefore \,\,\,144 = 16|b{|^2} \Rightarrow \,|b| = 3.$

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