If AO + OB = BO + OC , then A, B, C form - Vidyadip

MCQ

If $\overrightarrow {AO} + \overrightarrow {OB} = \overrightarrow {BO} + \overrightarrow {OC} ,$ then $A, B, C$ form

A
Equilateral triangle
B
Right angled triangle
✓
Isosceles triangle
D
Line

✓

Answer

Correct option: C.

Isosceles triangle

c
(c) $\overrightarrow {AB} = \overrightarrow {BC} $ $(as\, given)$.

Hence it is an isosceles triangle.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 10. vector algebra→STD 12 - 10. vector algebra — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

The angle of intersection of the parabolas $y^2 = 4 ax$ and $x^2 = 4ay$ at the origin is :

Let $\mathrm{A}(-1,1)$ and $\mathrm{B}(2,3)$ be two points and $\mathrm{P}$ be a variable point above the line $A B$ such that the area of $\triangle \mathrm{PAB}$ is $10$ . If the locus of $\mathrm{P}$ is $\mathrm{ax}+\mathrm{by}=15$, then $5 a+2 b$ is :

Choose the correct option from given four options$:\ \int\limits^{\frac{\pi}{4}}_{\frac{-\pi}{4}}\frac{\text{dx}}{1+\cos2\text{x}}$ is equal to:

The determinant $\begin{vmatrix}\text{b}^2-\text{ab}&\text{b}-\text{c}&\text{bc}-\text{ac}\\\text{ab}-\text{a}^2&\text{a}-\text{b}&\text{b}^2-\text{ab}\\\text{bc}-\text{ac}&\text{c}-\text{a}&\text{ab}-\text{a}^2\end{vmatrix}$ equals :

The function $\text{f}(\text{x})=\frac{\text{x}}{1+|\text{x}|}$ is:

Choose the correct answer in the following : The area of the circle $x^2 + y^2 = 16$ exterior to the parabola $y^2 = 6x$ is:

If $\vec{\text{x}}$ is a vector in the direction of $(2, -2, 1)$ of magnitude $6$ and $\vec{\text{y}}$ is a vector in the direction of $(1, 1, -1)$ of magnitude $\sqrt{3}$ then $\mid\vec{\text{x}}+2\vec{\text{y}}\mid=$

A fair coin is tossed a fixed number of times. If the probability of getting $7$ heads is equal to probability of getting $9$ heads, then the probability of getting $2$ heads is

If $f (x) =$ $\int\limits_0^{\pi /2} \frac{{\ell \,n\,\,(1\,\, + \,\,x\,\,{{\sin }^2}\,\,\theta )}}{{{{\sin }^2}\,\,\theta }}$ $d\, \theta$ , $x \geq 0$ then :

If $a$ and $ b$ are mutually perpendicular vectors, then ${(a + b)^2} = $